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Reversible Reactions and Chemical Equilibrium

Chemistry Grade 12 Difficulty 4/5

Beginning of the lesson

Reversible Reactions and Chemical Equilibrium

Equilibrium is a dynamic balance of opposing reaction rates, not a stopped reaction.

Learning goals: identify reversible reactions; explain dynamic equilibrium; write and interpret $K_c$; compare $Q_c$ with $K_c$; predict responses to concentration, pressure, and temperature; explain why catalysts do not change equilibrium composition.

1. Reversibility in a closed system

For $aA+bB\rightleftharpoons cC+dD$, the forward rate is initially greatest when reactants dominate. As products accumulate, the reverse rate rises. In a closed system at constant temperature the two rates can become equal. Concentrations then stay constant even though particles keep reacting.

Dynamic does not mean equal amounts
At equilibrium, $v_{forward}=v_{reverse}$. Reactant and product concentrations are constant, but they need not be equal. Their ratio is determined by temperature and the equilibrium constant.

2. Equilibrium constant and reaction quotient

For the homogeneous reaction above, $K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$. Exponents come from the balanced equation. Pure solids and pure liquids are omitted because their effective concentrations are constant. A large $K_c$ favors products; a small $K_c$ favors reactants. The reaction quotient $Q_c$ has the same form but uses the current, not necessarily equilibrium, concentrations.

ComparisonPrediction
$Q_c<K_c$Net forward reaction
$Q_c=K_c$Equilibrium
$Q_c>K_c$Net reverse reaction

3. Le Chatelier reasoning

  1. Write the balanced equation and count gaseous moles.

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