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Oxidation States and Formula Construction

Chemistry Grade 8 Difficulty 2/5

Beginning of the lesson

Oxidation states and neutral formulas

Oxidation states are bookkeeping values for electrons. Formula subscripts are chosen so the total contribution in a neutral compound is zero.

Learning goals

  • apply common oxidation-state rules;
  • find an unknown value from a charge sum;
  • construct and reduce neutral formulas;
  • use parentheses correctly with polyatomic ions.

1. Meaning and rules

An oxidation state is an assigned number that helps track electron ownership. It is written with sign first, such as +2 or −1. A monatomic ion’s oxidation state equals its charge, but atoms in covalent compounds may have assigned oxidation states without being full ions.

RuleExample
Free element = 0Na, O₂, Cl₂: 0
Monatomic ion = ion chargeMg²⁺: +2; Cl⁻: −1
Group 1 usually +1; group 2 usually +2NaCl; CaO
Fluorine in compounds = −1HF
Oxygen usually −2H₂O, CO₂
Hydrogen usually +1 with nonmetalsHCl, H₂O
Sum = total species chargeneutral compound: 0; ion: ion charge
1. write ionswith charges2. find leastcharge balance3. usesubscripts4. reduce andcheck sum

2. Finding an unknown oxidation state

Let the unknown be $x$, multiply each oxidation state by its subscript, and set the sum equal to the species charge. In CO₂, oxygen contributes $2(-2)=-4$, so $x-4=0$ and carbon is +4. In $SO_4^{2-}$, $x+4(-2)=-2$, so sulfur is +6.

3. Constructing a formula from ions

  1. Write the cation first and anion second with charges.
  2. Find the smallest numbers of ions that make total charge zero. A least-common-multiple method is safest.
  3. Write those counts as subscripts; omit subscript 1.

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  • Worked examples
  • Common mistakes and how to avoid them
  • Test questions: 15
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