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Taylor's Formula

Mathematics Grade 11 Difficulty 3/5

Beginning of the lesson

Taylor's Formula

Taylor's Formula is one of the most powerful tools in calculus — it lets us approximate any smooth function using polynomials. Think of it as building a polynomial "clone" of a function that matches its behavior near a specific point.

🎯 The Big Idea

Imagine you're standing at a point $x = a$ on a function's graph. You know the function's value there, its slope, its concavity, and all its higher derivatives. Taylor's Formula uses all of this information to build a polynomial that approximates the function near that point.

The more derivative information you use (higher degree), the better the approximation becomes!

📐 Formal Definition

If $f(x)$ is a function that has derivatives of all orders at $x = a$, then the Taylor series of $f$ centered at $a$ is:

$$f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!}(x - a)^n$$

Written out explicitly:

$$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f'''(a)}{3!}(x-a)^3 + \cdots$$

The $n$-th degree Taylor polynomial $T_n(x)$ is the partial sum:

$$T_n(x) = \sum_{k=0}^{n} \frac{f^{(k)}(a)}{k!}(x - a)^k$$
SymbolMeaning
$f^{(n)}(a)$The $n$-th derivative of $f$ evaluated at $x = a$
$n!$$n$ factorial: $n! = n \cdot (n-1) \cdot (n-2) \cdots 2 \cdot 1$
$a$The center of the expansion
$(x-a)^n$The displacement from center, raised to power $n$

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  • Test questions: 131
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