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Equation tan x = a

Mathematics Grade 10 Difficulty 2/5

Beginning of the lesson

Solving the Equation $\tan x = a$

📐 Understanding the Tangent Function

The tangent function is one of the fundamental trigonometric functions. Unlike sine and cosine, the tangent function has some unique properties that make solving $\tan x = a$ particularly elegant.

Key Properties of $\tan x$
  • Period: $\pi$ (or $180°$) — NOT $2\pi$ like sine and cosine
  • Domain: All real numbers except $x = \frac{\pi}{2} + n\pi$, where $n \in \mathbb{Z}$
  • Range: $(-\infty, +\infty)$ — tangent takes ALL real values
  • Vertical Asymptotes: At $x = \frac{\pi}{2} + n\pi$
  • Odd Function: $\tan(-x) = -\tan(x)$
💡 Why This Matters

Because $\tan x$ has range $(-\infty, +\infty)$, the equation $\tan x = a$ has a solution for every real number $a$. This is different from $\sin x = a$ or $\cos x = a$, which only have solutions when $|a| \leq 1$.

🎯 The General Solution Formula

$$\tan x = a \implies x = \arctan(a) + n\pi, \quad n \in \mathbb{Z}$$

Let's break this formula down step by step:

Step 1: Find the Principal Value

$x_0 = \arctan(a)$

This gives one specific solution in the interval $\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$

Step 2: Add the Period

$x = x_0 + n\pi$

Since $\tan x$ has period $\pi$, we add integer multiples of $\pi$

Step 3: State the Condition

$n \in \mathbb{Z}$

$n$ can be any integer: $\ldots, -2, -1, 0, 1, 2, \ldots$

🔑 Why Only $+n\pi$ (Not $\pm$)?

For $\sin x = a$, we need two families of solutions because sine reaches the same value at two different points in each full period. But tangent is strictly increasing on each branch and has period $\pi$, so it hits each value exactly once per period. That's why we only need one family of solutions: $x = \arctan(a) + n\pi$.

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