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Inverse Trigonometric Functions

Mathematics Grade 10 Difficulty 2/5

Beginning of the lesson

Inverse Trigonometric Functions

If trigonometric functions take an angle and return a ratio, then inverse trigonometric functions do the opposite — they take a ratio and return an angle.

🔄 The Big Idea

Consider the equation:

$\sin(\theta) = x$

If we know $x$ (the ratio) and want to find $\theta$ (the angle), we write:

$\theta = \sin^{-1}(x) = \arcsin(x)$

⚠️ Important: $\sin^{-1}(x)$ does NOT mean $\frac{1}{\sin(x)}$. The superscript $-1$ denotes the inverse function, not a reciprocal.
📋 The Three Main Inverse Trig Functions
FunctionNotationDomainRange (Principal Value)
Inverse Sine$\sin^{-1}(x)$ or $\arcsin(x)$$[-1, 1]$$\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$
Inverse Cosine$\cos^{-1}(x)$ or $\arccos(x)$$[-1, 1]$$[0, \pi]$
Inverse Tangent$\tan^{-1}(x)$ or $\arctan(x)$$(-\infty, \infty)$$\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$
🤔 Why Do We Need Restricted Ranges?

Trigonometric functions are periodic — they repeat their values. For example, $\sin(30°) = \sin(150°) = 0.5$. So if we ask "what angle has a sine of 0.5?", there are infinitely many answers!

To make the inverse a proper function (one output for each input), we restrict the range to a principal value branch. This ensures each input gives exactly one output.

$\arcsin$ returns angles in Q1 or Q4
$\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]$ or $[-90°, 90°]$
$\arccos$ returns angles in Q1 or Q2
$[0, \pi]$ or $[0°, 180°]$
$\arctan$ returns angles in Q1 or Q4
$\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$ or $(-90°, 90°)$

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