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The Fundamental Trigonometric Identity. Reduction Formulas

Mathematics Grade 9 Difficulty 2/5

Beginning of the lesson

The Fundamental Trigonometric Identity & Reduction Formulas

1. The Unit Circle Foundation

Let's start with the unit circle — a circle of radius 1 centered at the origin. Any point on this circle can be written as:

$P = (\cos\alpha,\; \sin\alpha)$

Since the point $P(x, y)$ lies on the circle $x^2 + y^2 = 1$, we can substitute $x = \cos\alpha$ and $y = \sin\alpha$ to get the most important identity in all of trigonometry.

Interactive visualization — available in the full lesson
Drag the slider to change the angle $\alpha$. Notice that no matter what angle you choose, $\cos^2\alpha + \sin^2\alpha$ always equals 1!

2. The Fundamental Trigonometric Identity

$$\sin^2\alpha + \cos^2\alpha = 1$$

This identity holds for every angle $\alpha$. It is sometimes called the Pythagorean Identity because it comes directly from the Pythagorean theorem applied to the unit circle.

Proof:

Consider a point $P$ on the unit circle making angle $\alpha$ with the positive $x$-axis.

  1. The coordinates of $P$ are $(\cos\alpha,\; \sin\alpha)$.
  2. The distance from the origin to $P$ is the radius $r = 1$.
  3. By the distance formula: $\sqrt{\cos^2\alpha + \sin^2\alpha} = 1$
  4. Squaring both sides: $\cos^2\alpha + \sin^2\alpha = 1$   $\blacksquare$
Useful Rearrangements:

Solving for $\sin^2\alpha$:

$\sin^2\alpha = 1 - \cos^2\alpha$

Solving for $\cos^2\alpha$:

$\cos^2\alpha = 1 - \sin^2\alpha$
Derived Identities (dividing through):

Divide by $\cos^2\alpha$:

$\tan^2\alpha + 1 = \dfrac{1}{\cos^2\alpha}$

Divide by $\sin^2\alpha$:

$1 + \cot^2\alpha = \dfrac{1}{\sin^2\alpha}$

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