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Triangle Area Theorem

Mathematics Grade 9 Difficulty 2/5

Beginning of the lesson

Triangle Area Theorem

📐 Formal Definition

The Triangle Area Theorem states that the area of a triangle is equal to one-half the product of its base and its corresponding height (altitude).

$$ A = \frac{1}{2} \times b \times h $$

where $b$ is the length of any side chosen as the base, and $h$ is the perpendicular distance from that base to the opposite vertex (the altitude).

🔍 Why Does This Formula Work? — The Proof

The key insight is that every triangle is exactly half of a parallelogram. Here's the reasoning:

  1. Start with any triangle with base $b$ and height $h$.
  2. Duplicate the triangle and rotate the copy 180°. Attach it to the original along one side.
  3. The result is a parallelogram with base $b$ and height $h$.
  4. The area of a parallelogram is $A_{\text{parallelogram}} = b \times h$.
  5. Since the triangle is exactly half the parallelogram: $A_{\text{triangle}} = \frac{1}{2} \times b \times h$.

This proof works for all triangles — acute, right, and obtuse!

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