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The Pythagorean Identity

Mathematics Algebra Difficulty 2/5

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The Pythagorean Identity

This single equation is the most important identity in trigonometry. It connects the sine and cosine of any angle through a beautifully simple relationship: their squares always add up to 1. We will derive it two ways — first from the Pythagorean theorem in a right triangle (which works for acute angles), and then from the equation of the unit circle (which works for all real numbers).

Derivation 1 — From the Pythagorean Theorem (acute angles)

Consider a right triangle whose hypotenuse has length 1. Place the triangle on the unit circle with one acute angle $\theta$ at the origin.

  1. The adjacent side (along the $x$-axis) has length $\cos\theta$.
  2. The opposite side (along the $y$-axis) has length $\sin\theta$.
  3. The hypotenuse equals the radius of the unit circle, which is $1$.

The Pythagorean theorem says $a^{2}+b^{2}=c^{2}$. Substituting $a=\sin\theta$, $b=\cos\theta$, $c=1$:

$$\sin^{2}\theta + \cos^{2}\theta = 1^{2} = 1$$
Limitation: This argument treats $\sin\theta$ and $\cos\theta$ as physical leg lengths, so it only applies when $0 < \theta < \dfrac{\pi}{2}$ (acute angles).
Derivation 2 — From the Unit Circle (all real numbers)

The unit circle is the set of all points $(x,y)$ satisfying

$$x^{2}+y^{2}=1.$$

By definition, for any real number $\theta$ the point on the unit circle at angle $\theta$ from the positive $x$-axis has coordinates

$$x = \cos\theta, \qquad y = \sin\theta.$$

Because this point lies on the circle, it must satisfy the circle's equation. Substituting:

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