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The Chain Rule

Mathematics Algebra Difficulty 2/5

Beginning of the lesson

1. The Setting: Why We Need a New Rule

1.1 Composite Functions Recalled

In the functions block you learned that a composite function is formed when the output of one function becomes the input of another. If $f$ and $g$ are functions, the composite $h = f \circ g$ is defined by

$$ h(x) = f\!\bigl(g(x)\bigr). $$

For example, $h(x) = \sin(x^3)$ is the composition of $f(u) = \sin u$ (outer) with $g(x) = x^3$ (inner). Similarly, $k(x) = \sqrt{3x^2+1}$ is $f(u) = \sqrt{u}$ composed with $g(x) = 3x^2+1$.

1.2 Why Existing Rules Fall Short

Key observation: We already know how to differentiate basic functions ($x^n$, $\sin x$, $\cos x$, $e^x$, $\ln x$, etc.) and how to handle sums, differences, products, quotients, and constant multiples. However, none of these rules tell us how to differentiate a composition.

Try differentiating $h(x) = (3x+1)^5$ using only the power rule. You would need to expand the fifth power first — tedious and error-prone. For $\sin(x^3)$ there is no expansion at all. We need a dedicated rule for compositions.

1.3 Numerical Evidence — Rates Multiply Through a Chain

Before stating the rule formally, let's build intuition with everyday "chain" reasoning:

Gear Analogy

Gear A turns 3 times for every turn of the input shaft. Gear B turns 2 times for every turn of Gear A. How fast does Gear B turn relative to the input?

$\text{Rate}_{B/\text{input}} = \underbrace{3}_{\text{A per input}} \times \underbrace{2}_{\text{B per A}} = 6$

The rates multiply through the chain of dependencies.

Unit Conversion Analogy

A car travels at 60 miles per hour. There are 1.609 km per mile. The speed in km/h is:

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