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Eigenvalues and Eigenvectors

Mathematics Algebra Difficulty 2/5

Beginning of the lesson

1. The Question That Starts Everything

The Central Question

Given a square matrix $A$ (viewed as a linear transformation), which nonzero vectors keep their direction — merely getting stretched, shrunk, or reversed?

When a matrix $A$ multiplies a vector $\mathbf{x}$, the result $A\mathbf{x}$ is usually a completely different vector — rotated, sheared, or otherwise redirected. But some special vectors come out parallel to themselves: the matrix only scales them. These are the eigenvectors, and the scale factor is the eigenvalue.

The Defining Equation
$$A\mathbf{x} = \lambda\mathbf{x}$$
  • $A$ is an $n \times n$ (square) matrix.
  • $\mathbf{x}$ is a nonzero vector — the eigenvector.
  • $\lambda$ is a scalar — the eigenvalue.

Why Exclude the Zero Vector?

The zero vector $\mathbf{0}$ satisfies $A\mathbf{0} = \lambda\mathbf{0}$ for every scalar $\lambda$ and every matrix $A$. It tells us nothing about the matrix — it "certifies nothing." That is why the definition insists $\mathbf{x} \neq \mathbf{0}$.

But Zero as an Eigenvalue Is Allowed!

Careful distinction — two different zeros:
ConceptStatusMeaning
$\mathbf{x} = \mathbf{0}$ (zero vector)ExcludedTrivially satisfies everything; gives no information.
$\lambda = 0$ (zero scalar)Allowed & meaningfulMeans $A\mathbf{x} = \mathbf{0}$: the matrix sends certain nonzero vectors to zero. These vectors lie in the kernel (null space) of $A$.

If $\lambda = 0$ is an eigenvalue, then $A$ is singular (not invertible), because it collapses some nonzero vectors to zero.

2. Geometric Intuition — A Gallery of Plane Transformations

Before computing anything, let's see eigenvectors in familiar transformations. These pictures should become your permanent mental furniture.

① Scaling Along Axes

$$A = \begin{pmatrix} 3 & 0 \\ 0 & 2 \end{pmatrix}$$

This stretches the $x$-axis by 3 and the $y$-axis by 2.

  • $\mathbf{e}_1 = \begin{pmatrix}1\\0\end{pmatrix}$ is an eigenvector with $\lambda = 3$.
  • $\mathbf{e}_2 = \begin{pmatrix}0\\1\end{pmatrix}$ is an eigenvector with $\lambda = 2$.

Every vector along an axis stays on that axis — only its length changes.

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