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The Second Remarkable Limit (the number e)

Mathematics Algebra Difficulty 2/5

Beginning of the lesson

Definition and Terminology

Naming convention: In the Russian-language mathematical tradition this result is called the второй замечательный предел — the "second remarkable (wonderful) limit". In English-language textbooks it is simply presented as the limit definition of e. The "first remarkable limit" is $\displaystyle\lim_{x\to 0}\frac{\sin x}{x}=1$, which you studied in the previous topic.
The Defining Limit

The number $e$ is defined as the limit of the sequence $a_n = \left(1+\dfrac{1}{n}\right)^{n}$ as $n\to\infty$:

$$ e \;:=\; \lim_{n\to\infty}\left(1+\frac{1}{n}\right)^{n} $$

The symbol $:=$ emphasises that this is a definition: the number $e$ is introduced as the value to which the sequence converges.

Its decimal expansion begins $e \approx 2.71828\,18284\,59045\ldots$ The number $e$ is irrational (proved by Euler, 1744) and in fact transcendental (proved by Hermite, 1873). We state these facts without proof.

Numerical Exploration

Let us compute $a_n$ for several values of $n$:

$n$$a_n = \left(1+\frac{1}{n}\right)^n$
$1$$2.00000$
$2$$2.25000$
$5$$2.48832$
$10$$2.59374$
$100$$2.70481$
$1\,000$$2.71692$
$10\,000$$2.71815$
$100\,000$$2.71827$

The terms increase steadily and approach $e\approx 2.71828$ from below. The convergence is monotone but slow: even at $n=1000$ the approximation agrees with $e$ only to the second decimal place.

Interactive Graph: $a_n = (1+1/n)^n$ approaching $e$
Interactive visualization — available in the full lesson

Why the Limit Exists — the Monotone-Bounded Argument

To prove that the sequence $\{a_n\}$ converges we show two things:

  1. The sequence is strictly increasing ($a_{n+1}>a_n$ for all $n$).
  2. The sequence is bounded above ($a_n < 3$ for all $n$).

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In the full lesson

  • The complete explanation
  • Worked examples
  • Common mistakes and how to avoid them
  • Test questions: 15
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