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Absolute and Conditional Convergence

Mathematics Algebra Difficulty 2/5

Beginning of the lesson

Why This Topic?

Up to now, every convergence test in your toolkit — comparison, ratio, root, integral — was designed for series with nonnegative terms. But many important series have terms that change sign. The alternating harmonic series $\displaystyle\sum_{n=1}^{\infty}\frac{(-1)^{n+1}}{n}=1-\tfrac12+\tfrac13-\tfrac14+\cdots$ is the simplest example: its terms are not all positive, so none of the nonnegative-term tests apply directly.

Two clean questions arise at the door of any mixed-sign series $\sum a_n$:

  1. Does the absolute series $\sum |a_n|$ converge?
  2. Does the original series $\sum a_n$ converge?

Four combinations seem possible a priori. One of them — "$\sum|a_n|$ converges but $\sum a_n$ diverges" — is excluded by the central theorem of this lesson. The remaining three define the trichotomy that classifies every series you will ever meet.

1. Alternating Series and the Leibniz Test

Definition — Alternating Series

A series is alternating if its terms strictly alternate in sign. The standard forms are:

$$\sum_{n=1}^{\infty}(-1)^{n+1}b_n = b_1 - b_2 + b_3 - b_4 + \cdots \qquad (b_n > 0)$$

$$\sum_{n=1}^{\infty}(-1)^{n}b_n = -b_1 + b_2 - b_3 + b_4 - \cdots \qquad (b_n > 0)$$

Theorem (Leibniz Alternating Series Test)

Suppose $\{b_n\}$ is a sequence of positive numbers satisfying:

  1. $b_{n+1}\le b_n$ for all $n$  (monotone decrease), and
  2. $\displaystyle\lim_{n\to\infty}b_n = 0$.

Then the alternating series $\displaystyle\sum_{n=1}^{\infty}(-1)^{n+1}b_n$ converges.

Proof — The Bracket Picture

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